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Lecture Notes 15 July 2010
Dr. B. Rajeevan 1
Dr. B. Rajeevan
Senior Lecturer
Department of Civil Engineering
Govt. College of Engineering Kannur
E-mail: rajeevan@gcek.ac.in
Mob: 9495 333 088
ContactTime: 4 pm – 5 pm
DESIGN OF STAIRS
STRUCTURAL DESIGN
15 July 2010 Dr. B. Rajeevan 2
Geometrical Classification
15 July 2010 Dr. B. Rajeevan 3
Geometrical Classification
15 July 2010 Dr. B. Rajeevan 4
15 July 2010 Dr. B. Rajeevan 5
Structural Classification-Stair
spanning longitudinally
15 July 2010 Dr. B. Rajeevan 6
Lecture Notes 15 July 2010
Dr. B. Rajeevan 2
15 July 2010 Dr. B. Rajeevan 7
Structural
Classification-Stair
spanning
transversely
Parts of a stair
15 July 2010 Dr. B. Rajeevan 8
15 July 2010 Dr. B. Rajeevan 9
Public Buildings
Rise = 150 mm
Tread = 270 mm to 300 mm
Residential Buildings
Rise = 160 mm
Tread = 250 mm
Number of rise in one flight < 12
15 July 2010 Dr. B. Rajeevan 10
Empirical relation
550 < (2R + G) < 750 (in mm)
(2R + G) = 600 (approx)
Principles of Design
• Cl. 33 of IS 456-2000
– Stair spanning horizontally (transversely)
– Stair spanning longitudinally
15 July 2010 Dr. B. Rajeevan 11
Stair spanning horizontally
15 July 2010 Dr. B. Rajeevan 12
Lecture Notes 15 July 2010
Dr. B. Rajeevan 3
Stair spanning horizontally
15 July 2010 Dr. B. Rajeevan 13
Stair spanning horizontally
15 July 2010 Dr. B. Rajeevan 14
Stair spanning longitudinally
Slab between beams
15 July 2010 Dr. B. Rajeevan 15
Stair spanning longitudinally
Slab between landings
15 July 2010 Dr. B. Rajeevan 16
Stair spanning longitudinally
Slab between walls
15 July 2010 Dr. B. Rajeevan 17
Dead Loads
15 July 2010 Dr. B. Rajeevan 18
Lecture Notes 15 July 2010
Dr. B. Rajeevan 4
Live Loads
• Live Load (IS 875)
– Residential building without overcrowding – 2 kN/m2
– Public building with overcrowding – 5 kN/m2
15 July 2010 Dr. B. Rajeevan 19
Depth of Section
• One way reinforced slab
– Longitudinally spanning – min thickness = W
– Transverse spanning – average depth of step; D/2
15 July 2010 Dr. B. Rajeevan 20
Structural Detailing
• Maximum BM – simply supported = wl2/8
– One half of tension steel taken to supports
• Maximum BM – slab built-in to beams at
supports = (0.9) wl2/8;
– 2/3 of tension steel to support as negative steel
• Maximum BM – slab continuous over beams at
supports = wl2/10;
– Full tension steel to support as negative steel
• Distributors– 0.0012bD or 0.0015bD in transverse
direction;
– Full tension steel to support as negative steel
15 July 2010 Dr. B. Rajeevan 21 15 July 2010 Dr. B. Rajeevan 22
15 July 2010 Dr. B. Rajeevan 23
Calculation of Dead Loads and
Effective Depth
• Transverse Stair
– Effective span = width of stair
– Individual steps of width = G and span = width of
stair
15 July 2010 Dr. B. Rajeevan 24
Lecture Notes 15 July 2010
Dr. B. Rajeevan 5
Calculation of Dead Loads and
Effective Depth
• Longitudinally spanning Stair
15 July 2010 Dr. B. Rajeevan 25
Design Example 1
A staircase has the following dimensions:
waist W = 75 mm; nosing N = 25 mm; rise R
=175 mm; going G = 225 mm. The live load
expected is 2 kN/m2. Calculate the factored
loads and effective depths for design if the
staircase is spanning (a) transversely , and (b)
longitudinally
15 July 2010 Dr. B. Rajeevan 26
15 July 2010 Dr. B. Rajeevan 27
Ref Step Calculations Output
1
wu=2.3kN/m
2
2 2 2 2
250 175 305
tan
1
25 1.08 /
1 2
0.225 2 0.45 /
, 1.5( ) 2.295 /u
B G R mm
Slab spanning seversely
RT
DL WB kN m
LL kN m
Design Load w DL LL kN m
cover
cos 2 2
161.5 ( 12 )
W R
d
mm Use mmdia
161.5d mm
15 July 2010 Dr. B. Rajeevan 28
Ref Step Calculations Output
1
wu=10.22 kN/m
2
2 2 2 2
250 175 305
tan
1
25 4.81 /
2
2 /
, 1.5( ) 10.22 /u
B G R mm
Slab spanning seversely
RT
DL WB kN m
G
LL kN m
Design Load w DL LL kN m
cover
2
54 ( 12 )
d W
mm Use mmdia
54d mm
Design Example 2
A longitudinal type of stair spans a distance of
3.75 m c/c of beams. R = 175 mm, T =250
mm. The treads have 15 mm granite finish
and consists of 15 steps. Use M25 grade
concrete and Fe 415 steel. Take Live load = 5
kN/m2. Width of stair = 1.5 m.
15 July 2010 Dr. B. Rajeevan 29 15 July 2010 Dr. B. Rajeevan 30
Ref Step Calculations Output
IS 456
Cl. 26.4
1 Thickness of waist slab, W
Assume l/d =30, d = 3750/30 = 125
W = 125 + cover + /2 = 125 + 15 + 6 = 146 mm =
150 mm (say)
d = 150 -15 -6 =129 mm W = 150 mm
d = 129 mm
2 Loads – Dead Load
DL =
Design Load = 1.5(DL + LL) = 18.48 kN/m2
SP 16
Table D
3 Bending Moment, Mu,
Check for Mu,lim
SP16
Table 3
4 Area of main steel
2 2 2 2
250 175 305B G R mm
21
25 23.5 7.32 /
2
RT FT
WB kN m
G G
2
18.48 /uw kN m
2
26 /
10
w
kN m
,limu uM M
2
2
1.56, 0.472
606
100
u
st
M
p
bd
pbd
A mm
Lecture Notes 15 July 2010
Dr. B. Rajeevan 6
15 July 2010 Dr. B. Rajeevan 31
Ref Step Calculations Output
SP 16
Table 96
5 Compute Spacing
Provide 12 mm dia bars at 180 mm c/c
Max spacing 3d or 300 mm
12 mm dia bars
at 180 mm c/c
IS 456
Cl. 25.5.2.1
SP 16
Table 96
6 Distributors
Provide 8 mm dia @ 270 mm c/c
Max spacing 5d or 450 mm
8 mm dia @ 270
mm c/c
IS456
Table 19
7 Shear Check
No shear
reinforcement
necessary
IS 456
Fig 4
8 Check for Deflection
(l/d)allowed = 1.2 x 26 =31.2
(l/d)assumed = 30 < 31.2
(l/d) ratio OK
2
,min 0.12 /100 180stA bD mm
34.65 ; / 0.27
2
0.36 ; Noshear reinforcement
v
c v c
w
V kN V bd MPa
MPa
Design Example 3
15 July 2010 Dr. B. Rajeevan 32
Design a waist slab type stair shown in Figure.
Landing slab A is supported on beams along JK
and PQ, while the waist slab and landing slab
B are spanning longitudinally as shown in
Figure. The finish load and Live load are 1
kN/m2 and 5 kN/m2 , respectively. Use R = 160
mm and T = 270 mm, concrete grade = M20
and steel grade = Fe 415
15 July 2010 Dr. B. Rajeevan 33 15 July 2010 Dr. B. Rajeevan 34
15 July 2010 Dr. B. Rajeevan 35 15 July 2010 Dr. B. Rajeevan 36
Lecture Notes 15 July 2010
Dr. B. Rajeevan 7
15 July 2010 Dr. B. Rajeevan 37 15 July 2010 Dr. B. Rajeevan 38
15 July 2010 Dr. B. Rajeevan 39 15 July 2010 Dr. B. Rajeevan 40
15 July 2010 Dr. B. Rajeevan 41 15 July 2010 Dr. B. Rajeevan 42
Lecture Notes 15 July 2010
Dr. B. Rajeevan 8
15 July 2010 Dr. B. Rajeevan 43 15 July 2010 Dr. B. Rajeevan 44
15 July 2010 Dr. B. Rajeevan 45
Homework
15 July 2010 Dr. B. Rajeevan 46
15 July 2010 Dr. B. Rajeevan 47 15 July 2010 Dr. B. Rajeevan 48
Lecture Notes 15 July 2010
Dr. B. Rajeevan 9
15 July 2010 Dr. B. Rajeevan 49 15 July 2010 Dr. B. Rajeevan 50
LOADS AT SECTION 1-1
15 July 2010 Dr. B. Rajeevan 51 15 July 2010 Dr. B. Rajeevan 52
15 July 2010 Dr. B. Rajeevan 53 15 July 2010 Dr. B. Rajeevan 54
Lecture Notes 15 July 2010
Dr. B. Rajeevan 10
15 July 2010 Dr. B. Rajeevan 55 15 July 2010 Dr. B. Rajeevan 56
15 July 2010 Dr. B. Rajeevan 57

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Stairs rajesh sir

  • 1. Lecture Notes 15 July 2010 Dr. B. Rajeevan 1 Dr. B. Rajeevan Senior Lecturer Department of Civil Engineering Govt. College of Engineering Kannur E-mail: rajeevan@gcek.ac.in Mob: 9495 333 088 ContactTime: 4 pm – 5 pm DESIGN OF STAIRS STRUCTURAL DESIGN 15 July 2010 Dr. B. Rajeevan 2 Geometrical Classification 15 July 2010 Dr. B. Rajeevan 3 Geometrical Classification 15 July 2010 Dr. B. Rajeevan 4 15 July 2010 Dr. B. Rajeevan 5 Structural Classification-Stair spanning longitudinally 15 July 2010 Dr. B. Rajeevan 6
  • 2. Lecture Notes 15 July 2010 Dr. B. Rajeevan 2 15 July 2010 Dr. B. Rajeevan 7 Structural Classification-Stair spanning transversely Parts of a stair 15 July 2010 Dr. B. Rajeevan 8 15 July 2010 Dr. B. Rajeevan 9 Public Buildings Rise = 150 mm Tread = 270 mm to 300 mm Residential Buildings Rise = 160 mm Tread = 250 mm Number of rise in one flight < 12 15 July 2010 Dr. B. Rajeevan 10 Empirical relation 550 < (2R + G) < 750 (in mm) (2R + G) = 600 (approx) Principles of Design • Cl. 33 of IS 456-2000 – Stair spanning horizontally (transversely) – Stair spanning longitudinally 15 July 2010 Dr. B. Rajeevan 11 Stair spanning horizontally 15 July 2010 Dr. B. Rajeevan 12
  • 3. Lecture Notes 15 July 2010 Dr. B. Rajeevan 3 Stair spanning horizontally 15 July 2010 Dr. B. Rajeevan 13 Stair spanning horizontally 15 July 2010 Dr. B. Rajeevan 14 Stair spanning longitudinally Slab between beams 15 July 2010 Dr. B. Rajeevan 15 Stair spanning longitudinally Slab between landings 15 July 2010 Dr. B. Rajeevan 16 Stair spanning longitudinally Slab between walls 15 July 2010 Dr. B. Rajeevan 17 Dead Loads 15 July 2010 Dr. B. Rajeevan 18
  • 4. Lecture Notes 15 July 2010 Dr. B. Rajeevan 4 Live Loads • Live Load (IS 875) – Residential building without overcrowding – 2 kN/m2 – Public building with overcrowding – 5 kN/m2 15 July 2010 Dr. B. Rajeevan 19 Depth of Section • One way reinforced slab – Longitudinally spanning – min thickness = W – Transverse spanning – average depth of step; D/2 15 July 2010 Dr. B. Rajeevan 20 Structural Detailing • Maximum BM – simply supported = wl2/8 – One half of tension steel taken to supports • Maximum BM – slab built-in to beams at supports = (0.9) wl2/8; – 2/3 of tension steel to support as negative steel • Maximum BM – slab continuous over beams at supports = wl2/10; – Full tension steel to support as negative steel • Distributors– 0.0012bD or 0.0015bD in transverse direction; – Full tension steel to support as negative steel 15 July 2010 Dr. B. Rajeevan 21 15 July 2010 Dr. B. Rajeevan 22 15 July 2010 Dr. B. Rajeevan 23 Calculation of Dead Loads and Effective Depth • Transverse Stair – Effective span = width of stair – Individual steps of width = G and span = width of stair 15 July 2010 Dr. B. Rajeevan 24
  • 5. Lecture Notes 15 July 2010 Dr. B. Rajeevan 5 Calculation of Dead Loads and Effective Depth • Longitudinally spanning Stair 15 July 2010 Dr. B. Rajeevan 25 Design Example 1 A staircase has the following dimensions: waist W = 75 mm; nosing N = 25 mm; rise R =175 mm; going G = 225 mm. The live load expected is 2 kN/m2. Calculate the factored loads and effective depths for design if the staircase is spanning (a) transversely , and (b) longitudinally 15 July 2010 Dr. B. Rajeevan 26 15 July 2010 Dr. B. Rajeevan 27 Ref Step Calculations Output 1 wu=2.3kN/m 2 2 2 2 2 250 175 305 tan 1 25 1.08 / 1 2 0.225 2 0.45 / , 1.5( ) 2.295 /u B G R mm Slab spanning seversely RT DL WB kN m LL kN m Design Load w DL LL kN m cover cos 2 2 161.5 ( 12 ) W R d mm Use mmdia 161.5d mm 15 July 2010 Dr. B. Rajeevan 28 Ref Step Calculations Output 1 wu=10.22 kN/m 2 2 2 2 2 250 175 305 tan 1 25 4.81 / 2 2 / , 1.5( ) 10.22 /u B G R mm Slab spanning seversely RT DL WB kN m G LL kN m Design Load w DL LL kN m cover 2 54 ( 12 ) d W mm Use mmdia 54d mm Design Example 2 A longitudinal type of stair spans a distance of 3.75 m c/c of beams. R = 175 mm, T =250 mm. The treads have 15 mm granite finish and consists of 15 steps. Use M25 grade concrete and Fe 415 steel. Take Live load = 5 kN/m2. Width of stair = 1.5 m. 15 July 2010 Dr. B. Rajeevan 29 15 July 2010 Dr. B. Rajeevan 30 Ref Step Calculations Output IS 456 Cl. 26.4 1 Thickness of waist slab, W Assume l/d =30, d = 3750/30 = 125 W = 125 + cover + /2 = 125 + 15 + 6 = 146 mm = 150 mm (say) d = 150 -15 -6 =129 mm W = 150 mm d = 129 mm 2 Loads – Dead Load DL = Design Load = 1.5(DL + LL) = 18.48 kN/m2 SP 16 Table D 3 Bending Moment, Mu, Check for Mu,lim SP16 Table 3 4 Area of main steel 2 2 2 2 250 175 305B G R mm 21 25 23.5 7.32 / 2 RT FT WB kN m G G 2 18.48 /uw kN m 2 26 / 10 w kN m ,limu uM M 2 2 1.56, 0.472 606 100 u st M p bd pbd A mm
  • 6. Lecture Notes 15 July 2010 Dr. B. Rajeevan 6 15 July 2010 Dr. B. Rajeevan 31 Ref Step Calculations Output SP 16 Table 96 5 Compute Spacing Provide 12 mm dia bars at 180 mm c/c Max spacing 3d or 300 mm 12 mm dia bars at 180 mm c/c IS 456 Cl. 25.5.2.1 SP 16 Table 96 6 Distributors Provide 8 mm dia @ 270 mm c/c Max spacing 5d or 450 mm 8 mm dia @ 270 mm c/c IS456 Table 19 7 Shear Check No shear reinforcement necessary IS 456 Fig 4 8 Check for Deflection (l/d)allowed = 1.2 x 26 =31.2 (l/d)assumed = 30 < 31.2 (l/d) ratio OK 2 ,min 0.12 /100 180stA bD mm 34.65 ; / 0.27 2 0.36 ; Noshear reinforcement v c v c w V kN V bd MPa MPa Design Example 3 15 July 2010 Dr. B. Rajeevan 32 Design a waist slab type stair shown in Figure. Landing slab A is supported on beams along JK and PQ, while the waist slab and landing slab B are spanning longitudinally as shown in Figure. The finish load and Live load are 1 kN/m2 and 5 kN/m2 , respectively. Use R = 160 mm and T = 270 mm, concrete grade = M20 and steel grade = Fe 415 15 July 2010 Dr. B. Rajeevan 33 15 July 2010 Dr. B. Rajeevan 34 15 July 2010 Dr. B. Rajeevan 35 15 July 2010 Dr. B. Rajeevan 36
  • 7. Lecture Notes 15 July 2010 Dr. B. Rajeevan 7 15 July 2010 Dr. B. Rajeevan 37 15 July 2010 Dr. B. Rajeevan 38 15 July 2010 Dr. B. Rajeevan 39 15 July 2010 Dr. B. Rajeevan 40 15 July 2010 Dr. B. Rajeevan 41 15 July 2010 Dr. B. Rajeevan 42
  • 8. Lecture Notes 15 July 2010 Dr. B. Rajeevan 8 15 July 2010 Dr. B. Rajeevan 43 15 July 2010 Dr. B. Rajeevan 44 15 July 2010 Dr. B. Rajeevan 45 Homework 15 July 2010 Dr. B. Rajeevan 46 15 July 2010 Dr. B. Rajeevan 47 15 July 2010 Dr. B. Rajeevan 48
  • 9. Lecture Notes 15 July 2010 Dr. B. Rajeevan 9 15 July 2010 Dr. B. Rajeevan 49 15 July 2010 Dr. B. Rajeevan 50 LOADS AT SECTION 1-1 15 July 2010 Dr. B. Rajeevan 51 15 July 2010 Dr. B. Rajeevan 52 15 July 2010 Dr. B. Rajeevan 53 15 July 2010 Dr. B. Rajeevan 54
  • 10. Lecture Notes 15 July 2010 Dr. B. Rajeevan 10 15 July 2010 Dr. B. Rajeevan 55 15 July 2010 Dr. B. Rajeevan 56 15 July 2010 Dr. B. Rajeevan 57
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